Aufgabe 4361 - NaWi@HTL

`y(1) = 3sin(2t + π/2)`

`y(2) = -5sin(t - π/2)`

`y(3) = 7sin(5t + 3π/4)`

`y(3) = y(4) = 10cos(0,5t - π)`

`y(1) = 3sin(2t + π/2)`

`y(2) = -5sin(t - π/2)`

`y(3) = 7sin(5t + 3π/4)`

`y(3) = y(4) = 10cos(0,5t - π)`

`y(1) = 3sin(2t + π/2)`

`y(2) = -5sin(t - π/2)`

`y(3) = 7sin(5t + 3π/4)`

`y(3) = y(4) = 10cos(0,5t - π)`

`y(1) = 3sin(2t + π/2)`

`y(2) = -5sin(t - π/2)`

`y(3) = 7sin(5t + 3π/4)`

`y(3) = y(4) = 10cos(0,5t - π)`

Aufgabe Nr. 4361

	`y(1) = 3sin(2t + π/2)` `y(2) = -5sin(t - π/2)` `y(3) = 7sin(5t + 3π/4)` `y(3) = y(4) = 10cos(0,5t - π)`
	`y(1) = 3sin(2t + π/2)` `y(2) = -5sin(t - π/2)` `y(3) = 7sin(5t + 3π/4)` `y(3) = y(4) = 10cos(0,5t - π)`
	`y(1) = 3sin(2t + π/2)` `y(2) = -5sin(t - π/2)` `y(3) = 7sin(5t + 3π/4)` `y(3) = y(4) = 10cos(0,5t - π)`
	`y(1) = 3sin(2t + π/2)` `y(2) = -5sin(t - π/2)` `y(3) = 7sin(5t + 3π/4)` `y(3) = y(4) = 10cos(0,5t - π)`